x^2+12x=12

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Solution for x^2+12x=12 equation:


Simplifying
x2 + 12x = 12

Reorder the terms:
12x + x2 = 12

Solving
12x + x2 = 12

Solving for variable 'x'.

Reorder the terms:
-12 + 12x + x2 = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + 12x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '12' to each side of the equation.
-12 + 12x + 12 + x2 = 0 + 12

Reorder the terms:
-12 + 12 + 12x + x2 = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 12x + x2 = 0 + 12
12x + x2 = 0 + 12

Combine like terms: 0 + 12 = 12
12x + x2 = 12

The x term is 12x.  Take half its coefficient (6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
12x + 36 + x2 = 12 + 36

Reorder the terms:
36 + 12x + x2 = 12 + 36

Combine like terms: 12 + 36 = 48
36 + 12x + x2 = 48

Factor a perfect square on the left side:
(x + 6)(x + 6) = 48

Calculate the square root of the right side: 6.92820323

Break this problem into two subproblems by setting 
(x + 6) equal to 6.92820323 and -6.92820323.

Subproblem 1

x + 6 = 6.92820323 Simplifying x + 6 = 6.92820323 Reorder the terms: 6 + x = 6.92820323 Solving 6 + x = 6.92820323 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + x = 6.92820323 + -6 Combine like terms: 6 + -6 = 0 0 + x = 6.92820323 + -6 x = 6.92820323 + -6 Combine like terms: 6.92820323 + -6 = 0.92820323 x = 0.92820323 Simplifying x = 0.92820323

Subproblem 2

x + 6 = -6.92820323 Simplifying x + 6 = -6.92820323 Reorder the terms: 6 + x = -6.92820323 Solving 6 + x = -6.92820323 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + x = -6.92820323 + -6 Combine like terms: 6 + -6 = 0 0 + x = -6.92820323 + -6 x = -6.92820323 + -6 Combine like terms: -6.92820323 + -6 = -12.92820323 x = -12.92820323 Simplifying x = -12.92820323

Solution

The solution to the problem is based on the solutions from the subproblems. x = {0.92820323, -12.92820323}

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